Include a -1 in a design matrix using R's formula notation

by rcorty   Last Updated October 07, 2017 21:19 PM

I am building a statistical model for basketball games. I have a data.frame like this:

winner     loser     date
teamA      teamB     2003-01-01
teamB      teamC     2003-01-03
...        ...       ...

Two important things to note about this data set is that each team has at least 5 wins and at least 5 losses and all the teams are in the same league (so, though there are teams that haven't played each other, there are no pairs of teams that haven't played any of the same teams.)

My first thought is to use logistic regression to capture this sort of logic:

$p($team_A_wins$) = $logit$($team_A_skill$ - $team_B_skill$)$

But I can't figure out how to get the appropriate design matrix with R's formula notation.

I ended up sort of quasi-manually computing it in this way:

winner_mat <- model.matrix(object = ~ winner,
                           data = data_for_model1)

loser_mat <- model.matrix(object = ~ loser,
                          data = data_for_model1)

X <- winner_mat - loser_mat

X constructed this way, can be used in glm and gives sensible results:

fit1 <- glm.fit(x = X,
                y = rep(1, nrow(X)),
                family = binomial())

tail(sort(coef(fit1)))

So my question is this -- I'm happy with the design matrix I've constructed, but was there a better way to construct it, e.g. using R's formula notation?



Related Questions



Difference between genmod SAS and glm R

Updated July 24, 2015 16:08 PM